Friday, 23 January 2026

Exercise (4.4).2

Determine a prime factor of the following composite Mersenne numbers $M_q$:

(a) $M_{43}$

(b) $M_{73}$


We remind ourselves of Proposition (4.23).  Let $q$ be an odd prime. Any prime factor $p$ of the composite Mersenne $M_q = 2^q− 1$ is of the form $p= 2kq + 1$ where $k$ is an integer.

Note that this does not mean all primes of the form $p=2kq+$ are factors of $M_q$. It means that those that are factors, have this form. That is, factor implies form, not form implies factor.


We also remind ourselves of Proposition (4.24). Let $q$ be an odd prime. Any prime factor $p$ of $M_q = 2^q -1 $ is of the form $p \equiv \pm 1 \pmod 8$. 

Again, this not mean all primes of the form are factors, only that factors have this form.


(a) $M_{43}=2^{43}-1$. 

We can't use Proposition (4.19)(a), because setting $n=43$ gives $p=2(43)+1=87$ which is not prime. 

We can't use Corollary (4.21) because $43$ is not a Germain prime as $2(43)+1=87$ is not prime.

Let's try finding candidates that conform to propositions (4.23) and (4.24), which are necessary but not sufficient conditions.

The following table shows values of $p=2k(43)+1$, whether it is prime, and $p \mod 8$.

kp=2k(43)+1prime?p mod 8
187no7
2173yes5
3259no3
4345no1
5431yes7
6517no5
7603no3

We can see $k=5$ gives $p=431$, which is prime, and is congruent to -1 modulo 8, and so is a candidate factor of $2^{43}-1$.

Using a calculator confirms that $431 \mid 2^{43}-1$. And so 431 is a prime factor of $2^{43}-1$.


(b) $M_{73}=2^{43}-1$. 

We can't use Proposition (4.19)(a), because setting $n=73$ gives $p=2(73)+1=147$ which is not prime. 

We can't use Corollary (4.21) because $73$ is not a Germain prime as $2(73)+1=147$ is not prime.

Let's try finding candidates that conform to propositions (4.23) and (4.24), which are necessary but not sufficient conditions.

The following table shows values of $p=2k(73)+1$, whether it is prime, and $p \mod 8$.

kp=2k(73)+1prime?p mod 8
1147no3
2293yes5
3439yes7
4585no1
5731no3
6877yes5
71023no7

We can see $k=3$ gives $p=439$, which is prime and also congruent to -1 modulo 8, an so is a candidate factor of $2^{73}-1$.

Using a computer algebra system (link) confirms $439 \mid 2^{73}-1$. And so 439 is a prime factor of $2^{73}-1$.


Note: The author's solutions suggest that a number that conforms to propositions (4.23) and (4.24) is a prime factor. This is not correct. The propositions provide necessary but not sufficient conditions for a prime factor of a Mersenne number.